Base | Representation |
---|---|
bin | 10011100000011010011… |
… | …111111011011111011111 |
3 | 11202010222222000200200011 |
4 | 103200122133323133133 |
5 | 133430242414432421 |
6 | 2503445545544051 |
7 | 165563130116155 |
oct | 23403237733737 |
9 | 4663888020604 |
10 | 1340474374111 |
11 | 477545924554 |
12 | 1979621a5027 |
13 | 9953852ba32 |
14 | 48c44b5b3d5 |
15 | 24d073b24e1 |
hex | 1381a7fb7df |
1340474374111 has 4 divisors (see below), whose sum is σ = 1340830792224. Its totient is φ = 1340117956000.
The previous prime is 1340474374097. The next prime is 1340474374159. The reversal of 1340474374111 is 1114734740431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1340474374111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1340474374181) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 178203415 + ... + 178210936.
It is an arithmetic number, because the mean of its divisors is an integer number (335207698056).
Almost surely, 21340474374111 is an apocalyptic number.
1340474374111 is a deficient number, since it is larger than the sum of its proper divisors (356418113).
1340474374111 is an equidigital number, since it uses as much as digits as its factorization.
1340474374111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 356418112.
The product of its (nonzero) digits is 112896, while the sum is 40.
The spelling of 1340474374111 in words is "one trillion, three hundred forty billion, four hundred seventy-four million, three hundred seventy-four thousand, one hundred eleven".
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