Base | Representation |
---|---|
bin | 11000111110010000… |
… | …11111000110010101 |
3 | 1021121101001100110001 |
4 | 30133020133012111 |
5 | 204424222020432 |
6 | 10054215131301 |
7 | 653146330204 |
oct | 143710370625 |
9 | 37541040401 |
10 | 13407220117 |
11 | 5760031a05 |
12 | 2722073b31 |
13 | 1358870755 |
14 | 91288d23b |
15 | 53708e9e7 |
hex | 31f21f195 |
13407220117 has 2 divisors, whose sum is σ = 13407220118. Its totient is φ = 13407220116.
The previous prime is 13407220093. The next prime is 13407220133. The reversal of 13407220117 is 71102270431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12404167876 + 1003052241 = 111374^2 + 31671^2 .
It is an emirp because it is prime and its reverse (71102270431) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13407220117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13407220157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6703610058 + 6703610059.
It is an arithmetic number, because the mean of its divisors is an integer number (6703610059).
Almost surely, 213407220117 is an apocalyptic number.
It is an amenable number.
13407220117 is a deficient number, since it is larger than the sum of its proper divisors (1).
13407220117 is an equidigital number, since it uses as much as digits as its factorization.
13407220117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2352, while the sum is 28.
Adding to 13407220117 its reverse (71102270431), we get a palindrome (84509490548).
The spelling of 13407220117 in words is "thirteen billion, four hundred seven million, two hundred twenty thousand, one hundred seventeen".
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