Base | Representation |
---|---|
bin | 11000111110110000… |
… | …11111000110101111 |
3 | 1021121122221102222121 |
4 | 30133120133012233 |
5 | 204431310230242 |
6 | 10054445053411 |
7 | 653230066444 |
oct | 143730370657 |
9 | 37548842877 |
10 | 13411414447 |
11 | 57624371a2 |
12 | 2723557267 |
13 | 13596ab8c2 |
14 | 9132619cb |
15 | 53761c667 |
hex | 31f61f1af |
13411414447 has 2 divisors, whose sum is σ = 13411414448. Its totient is φ = 13411414446.
The previous prime is 13411414411. The next prime is 13411414477. The reversal of 13411414447 is 74441411431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13411414447 - 27 = 13411414319 is a prime.
It is a super-3 number, since 3×134114144473 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13411414477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705707223 + 6705707224.
It is an arithmetic number, because the mean of its divisors is an integer number (6705707224).
Almost surely, 213411414447 is an apocalyptic number.
13411414447 is a deficient number, since it is larger than the sum of its proper divisors (1).
13411414447 is an equidigital number, since it uses as much as digits as its factorization.
13411414447 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 21504, while the sum is 34.
Adding to 13411414447 its reverse (74441411431), we get a palindrome (87852825878).
The spelling of 13411414447 in words is "thirteen billion, four hundred eleven million, four hundred fourteen thousand, four hundred forty-seven".
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