Base | Representation |
---|---|
bin | 10011100001001011101… |
… | …101100000000100101011 |
3 | 11202020010111121121121021 |
4 | 103201023231200010223 |
5 | 133433440300443103 |
6 | 2504103522153311 |
7 | 165622444005505 |
oct | 23411355400453 |
9 | 4666114547537 |
10 | 1341300015403 |
11 | 477929989027 |
12 | 197b527b2837 |
13 | 9963a5bb98a |
14 | 48cc267cd75 |
15 | 24d54b01bbd |
hex | 1384bb6012b |
1341300015403 has 8 divisors (see below), whose sum is σ = 1342939772480. Its totient is φ = 1339660614600.
The previous prime is 1341300015389. The next prime is 1341300015437. The reversal of 1341300015403 is 3045100031431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1341300015403 - 25 = 1341300015371 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1341300010403) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7878328 + ... + 8046778.
It is an arithmetic number, because the mean of its divisors is an integer number (167867471560).
Almost surely, 21341300015403 is an apocalyptic number.
1341300015403 is a deficient number, since it is larger than the sum of its proper divisors (1639757077).
1341300015403 is an equidigital number, since it uses as much as digits as its factorization.
1341300015403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 178137.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 1341300015403 its reverse (3045100031431), we get a palindrome (4386400046834).
The spelling of 1341300015403 in words is "one trillion, three hundred forty-one billion, three hundred million, fifteen thousand, four hundred three".
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