134211232640437 has 2 divisors, whose sum is σ = 134211232640438. Its totient is φ = 134211232640436.

The previous prime is 134211232640389. The next prime is 134211232640477. The reversal of 134211232640437 is 734046232112431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 132369419946481 + 1841812693956 = 11505191^2 + 1357134^2 .

It is a cyclic number.

It is not a de Polignac number, because 134211232640437 - 2⁴³ = 125415139618229 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 134211232640393 and 134211232640402.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134211232640477) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67105616320218 + 67105616320219.

It is an arithmetic number, because the mean of its divisors is an integer number (67105616320219).

Almost surely, 2^{134211232640437} is an apocalyptic number.

It is an amenable number.

134211232640437 is a deficient number, since it is larger than the sum of its proper divisors (1).

134211232640437 is an equidigital number, since it uses as much as digits as its factorization.

134211232640437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 580608, while the sum is 43.

Adding to 134211232640437 its reverse (734046232112431), we get a palindrome (868257464752868).

The spelling of 134211232640437 in words is "one hundred thirty-four trillion, two hundred eleven billion, two hundred thirty-two million, six hundred forty thousand, four hundred thirty-seven".