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134224210202 = 267112105101
BaseRepresentation
bin111110100000001100…
…0101110100100011010
3110211110022112100122112
41331000120232210122
54144342344211302
6141354534352322
712461125650665
oct1750030564432
9424408470575
10134224210202
1151a19081845
122201b4bb6a2
13c8710a90b4
1466d45046dc
153758b26552
hex1f4062e91a

134224210202 has 4 divisors (see below), whose sum is σ = 201336315306. Its totient is φ = 67112105100.

The previous prime is 134224210201. The next prime is 134224210213. The reversal of 134224210202 is 202012422431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 127398311041 + 6825899161 = 356929^2 + 82619^2 .

It is a super-2 number, since 2×1342242102022 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (134224210201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33556052549 + ... + 33556052552.

Almost surely, 2134224210202 is an apocalyptic number.

134224210202 is a deficient number, since it is larger than the sum of its proper divisors (67112105104).

134224210202 is an equidigital number, since it uses as much as digits as its factorization.

134224210202 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67112105103.

The product of its (nonzero) digits is 1536, while the sum is 23.

Adding to 134224210202 its reverse (202012422431), we get a palindrome (336236632633).

The spelling of 134224210202 in words is "one hundred thirty-four billion, two hundred twenty-four million, two hundred ten thousand, two hundred two".

Divisors: 1 2 67112105101 134224210202