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134224214081 is a prime number
BaseRepresentation
bin111110100000001100…
…0101111100001000001
3110211110022112112222012
41331000120233201001
54144342344322311
6141354534422305
712461125665206
oct1750030574101
9424408475865
10134224214081
1151a19084751
122201b501995
13c8710aaaa9
1466d4505cad
153758b2778b
hex1f4062f841

134224214081 has 2 divisors, whose sum is σ = 134224214082. Its totient is φ = 134224214080.

The previous prime is 134224214063. The next prime is 134224214083. The reversal of 134224214081 is 180412422431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 75559014400 + 58665199681 = 274880^2 + 242209^2 .

It is a cyclic number.

It is not a de Polignac number, because 134224214081 - 226 = 134157105217 is a prime.

It is a super-2 number, since 2×1342242140812 (a number of 23 digits) contains 22 as substring.

Together with 134224214083, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (134224214083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67112107040 + 67112107041.

It is an arithmetic number, because the mean of its divisors is an integer number (67112107041).

Almost surely, 2134224214081 is an apocalyptic number.

It is an amenable number.

134224214081 is a deficient number, since it is larger than the sum of its proper divisors (1).

134224214081 is an equidigital number, since it uses as much as digits as its factorization.

134224214081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12288, while the sum is 32.

The spelling of 134224214081 in words is "one hundred thirty-four billion, two hundred twenty-four million, two hundred fourteen thousand, eighty-one".