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134224214281 is a prime number
BaseRepresentation
bin111110100000001100…
…0101111100100001001
3110211110022112120020121
41331000120233210021
54144342344324111
6141354534423241
712461125665613
oct1750030574411
9424408476217
10134224214281
1151a19084913
122201b501b21
13c8710aac01
1466d4505db3
153758b27871
hex1f4062f909

134224214281 has 2 divisors, whose sum is σ = 134224214282. Its totient is φ = 134224214280.

The previous prime is 134224214171. The next prime is 134224214329. The reversal of 134224214281 is 182412422431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 134073145600 + 151068681 = 366160^2 + 12291^2 .

It is a cyclic number.

It is not a de Polignac number, because 134224214281 - 211 = 134224212233 is a prime.

It is a super-2 number, since 2×1342242142812 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (134224214081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67112107140 + 67112107141.

It is an arithmetic number, because the mean of its divisors is an integer number (67112107141).

Almost surely, 2134224214281 is an apocalyptic number.

It is an amenable number.

134224214281 is a deficient number, since it is larger than the sum of its proper divisors (1).

134224214281 is an equidigital number, since it uses as much as digits as its factorization.

134224214281 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 24576, while the sum is 34.

The spelling of 134224214281 in words is "one hundred thirty-four billion, two hundred twenty-four million, two hundred fourteen thousand, two hundred eighty-one".