Base | Representation |
---|---|
bin | 10011100010001111011… |
… | …001101010100110100111 |
3 | 11202100001122112122211012 |
4 | 103202033121222212213 |
5 | 133443302012310333 |
6 | 2504412331132435 |
7 | 165662543614262 |
oct | 23421731524647 |
9 | 4670048478735 |
10 | 1342435666343 |
11 | 478361a33422 |
12 | 19820aba411b |
13 | 9978b972795 |
14 | 48d8d41bcd9 |
15 | 24dbe67ae48 |
hex | 1388f66a9a7 |
1342435666343 has 16 divisors (see below), whose sum is σ = 1394795719680. Its totient is φ = 1291054476096.
The previous prime is 1342435666339. The next prime is 1342435666367. The reversal of 1342435666343 is 3436665342431.
It is a cyclic number.
It is not a de Polignac number, because 1342435666343 - 22 = 1342435666339 is a prime.
It is a super-3 number, since 3×13424356663433 (a number of 37 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1342435666291 and 1342435666300.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1342435662343) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6252803 + ... + 6463931.
It is an arithmetic number, because the mean of its divisors is an integer number (87174732480).
Almost surely, 21342435666343 is an apocalyptic number.
1342435666343 is a deficient number, since it is larger than the sum of its proper divisors (52360053337).
1342435666343 is a wasteful number, since it uses less digits than its factorization.
1342435666343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 213446.
The product of its digits is 11197440, while the sum is 50.
The spelling of 1342435666343 in words is "one trillion, three hundred forty-two billion, four hundred thirty-five million, six hundred sixty-six thousand, three hundred forty-three".
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