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13431014343055 = 52686202868611
BaseRepresentation
bin1100001101110010011011…
…0101101100000110001111
31202112222210111000202201201
43003130212311230012033
53230023204132434210
644322042305450331
72554234025150551
oct303344665540617
952488714022651
1013431014343055
1143090744a6071
12160b02b6409a7
1376570187b32a
143460c92354d1
15184588c7053a
hexc3726d6c18f

13431014343055 has 4 divisors (see below), whose sum is σ = 16117217211672. Its totient is φ = 10744811474440.

The previous prime is 13431014343049. The next prime is 13431014343059. The reversal of 13431014343055 is 55034341013431.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2k-13431014343055 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13431014343059) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1343101434301 + ... + 1343101434310.

It is an arithmetic number, because the mean of its divisors is an integer number (4029304302918).

Almost surely, 213431014343055 is an apocalyptic number.

13431014343055 is a deficient number, since it is larger than the sum of its proper divisors (2686202868617).

13431014343055 is an equidigital number, since it uses as much as digits as its factorization.

13431014343055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2686202868616.

The product of its (nonzero) digits is 129600, while the sum is 37.

Adding to 13431014343055 its reverse (55034341013431), we get a palindrome (68465355356486).

The spelling of 13431014343055 in words is "thirteen trillion, four hundred thirty-one billion, fourteen million, three hundred forty-three thousand, fifty-five".

Divisors: 1 5 2686202868611 13431014343055