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134331444241 = 213163036811
BaseRepresentation
bin111110100011011000…
…1110010110000010001
3110211201210022102002121
41331012301302300101
54200102322203431
6141413325014241
712463600302451
oct1750661626021
9424653272077
10134331444241
1151a73664315
122204b3b4381
13c88a3834a7
146704859d61
153763259611
hex1f46c72c11

134331444241 has 4 divisors (see below), whose sum is σ = 134394483184. Its totient is φ = 134268405300.

The previous prime is 134331444227. The next prime is 134331444253. The reversal of 134331444241 is 142444133431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134331444241 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 134331444197 and 134331444206.

It is not an unprimeable number, because it can be changed into a prime (134331444641) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31516275 + ... + 31520536.

It is an arithmetic number, because the mean of its divisors is an integer number (33598620796).

Almost surely, 2134331444241 is an apocalyptic number.

It is an amenable number.

134331444241 is a deficient number, since it is larger than the sum of its proper divisors (63038943).

134331444241 is an equidigital number, since it uses as much as digits as its factorization.

134331444241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 63038942.

The product of its digits is 55296, while the sum is 34.

Adding to 134331444241 its reverse (142444133431), we get a palindrome (276775577672).

The spelling of 134331444241 in words is "one hundred thirty-four billion, three hundred thirty-one million, four hundred forty-four thousand, two hundred forty-one".

Divisors: 1 2131 63036811 134331444241