Base | Representation |
---|---|
bin | 11001000001111011… |
… | …11001100100000001 |
3 | 1021200111222002122001 |
4 | 30200331321210001 |
5 | 210010111434421 |
6 | 10101234544001 |
7 | 654002052463 |
oct | 144075714401 |
9 | 37614862561 |
10 | 13437999361 |
11 | 57764448a6 |
12 | 2730438001 |
13 | 1362059317 |
14 | 9169c2133 |
15 | 539b1e691 |
hex | 320f79901 |
13437999361 has 4 divisors (see below), whose sum is σ = 13495673412. Its totient is φ = 13380325312.
The previous prime is 13437999301. The next prime is 13437999371. The reversal of 13437999361 is 16399973431.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 16399973431 = 31 ⋅529031401.
It can be written as a sum of positive squares in 2 ways, for example, as 7050792961 + 6387206400 = 83969^2 + 79920^2 .
It is a cyclic number.
It is not a de Polignac number, because 13437999361 - 27 = 13437999233 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13437999301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28836676 + ... + 28837141.
It is an arithmetic number, because the mean of its divisors is an integer number (3373918353).
Almost surely, 213437999361 is an apocalyptic number.
It is an amenable number.
13437999361 is a deficient number, since it is larger than the sum of its proper divisors (57674051).
13437999361 is an equidigital number, since it uses as much as digits as its factorization.
13437999361 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 57674050.
The product of its digits is 3306744, while the sum is 55.
The spelling of 13437999361 in words is "thirteen billion, four hundred thirty-seven million, nine hundred ninety-nine thousand, three hundred sixty-one".
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