Base | Representation |
---|---|
bin | 11110100100010111010010… |
… | …011100111001000011110000 |
3 | 122122000100220210211020120100 |
4 | 132210113102130321003300 |
5 | 120110132214320334300 |
6 | 1153533004442312400 |
7 | 40213664005042335 |
oct | 3644272234710360 |
9 | 578010823736510 |
10 | 134440302121200 |
11 | 399228a2772379 |
12 | 130b35211b8700 |
13 | 5a0288753293a |
14 | 252ad3403498c |
15 | 108217a211700 |
hex | 7a45d27390f0 |
134440302121200 has 1080 divisors, whose sum is σ = 496028670302880. Its totient is φ = 33714156441600.
The previous prime is 134440302121159. The next prime is 134440302121249. The reversal of 134440302121200 is 2121203044431.
134440302121200 is a `hidden beast` number, since 1 + 3 + 4 + 440 + 3 + 0 + 2 + 1 + 212 + 0 + 0 = 666.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 215 ways as a sum of consecutive naturals, for example, 130397964685 + ... + 130397965715.
It is an arithmetic number, because the mean of its divisors is an integer number (459285805836).
Almost surely, 2134440302121200 is an apocalyptic number.
134440302121200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 134440302121200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (248014335151440).
134440302121200 is an abundant number, since it is smaller than the sum of its proper divisors (361588368181680).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134440302121200 is a wasteful number, since it uses less digits than its factorization.
134440302121200 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1735 (or 1702 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 27.
Adding to 134440302121200 its reverse (2121203044431), we get a palindrome (136561505165631).
The spelling of 134440302121200 in words is "one hundred thirty-four trillion, four hundred forty billion, three hundred two million, one hundred twenty-one thousand, two hundred".
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