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13525440151 = 311441930259
BaseRepresentation
bin11001001100010110…
…11101011010010111
31021220121111112211211
430212023131122113
5210200003041101
610114041042251
7656113226056
oct144613353227
937817445754
1013525440151
115810838413
122755786387
1313771c3432
1492446439d
15542642c51
hex3262dd697

13525440151 has 8 divisors (see below), whose sum is σ = 13963174400. Its totient is φ = 13087795320.

The previous prime is 13525440143. The next prime is 13525440179. The reversal of 13525440151 is 15104452531.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13525440151 - 23 = 13525440143 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (31).

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13525444151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 431860 + ... + 462118.

It is an arithmetic number, because the mean of its divisors is an integer number (1745396800).

Almost surely, 213525440151 is an apocalyptic number.

13525440151 is a deficient number, since it is larger than the sum of its proper divisors (437734249).

13525440151 is a wasteful number, since it uses less digits than its factorization.

13525440151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44709.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 13525440151 its reverse (15104452531), we get a palindrome (28629892682).

The spelling of 13525440151 in words is "thirteen billion, five hundred twenty-five million, four hundred forty thousand, one hundred fifty-one".

Divisors: 1 31 14419 30259 446989 938029 436304521 13525440151