Base | Representation |
---|---|
bin | 11001001101000010… |
… | …10000110001001011 |
3 | 1021221000020220212120 |
4 | 30212201100301023 |
5 | 210202433434111 |
6 | 10114403342323 |
7 | 656212632015 |
oct | 144641206113 |
9 | 37830226776 |
10 | 13531155531 |
11 | 5813a91473 |
12 | 27576819a3 |
13 | 1378444a0a |
14 | 9251111b5 |
15 | 542dc1406 |
hex | 326850c4b |
13531155531 has 4 divisors (see below), whose sum is σ = 18041540712. Its totient is φ = 9020770352.
The previous prime is 13531155529. The next prime is 13531155551. The reversal of 13531155531 is 13555113531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13531155531 - 21 = 13531155529 is a prime.
It is a super-2 number, since 2×135311555312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13531155492 and 13531155501.
It is not an unprimeable number, because it can be changed into a prime (13531155511) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2255192586 + ... + 2255192591.
It is an arithmetic number, because the mean of its divisors is an integer number (4510385178).
Almost surely, 213531155531 is an apocalyptic number.
13531155531 is a deficient number, since it is larger than the sum of its proper divisors (4510385181).
13531155531 is an equidigital number, since it uses as much as digits as its factorization.
13531155531 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4510385180.
The product of its digits is 16875, while the sum is 33.
The spelling of 13531155531 in words is "thirteen billion, five hundred thirty-one million, one hundred fifty-five thousand, five hundred thirty-one".
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