Base | Representation |
---|---|
bin | 1100010011110010000101… |
… | …0101111010110011000000 |
3 | 1202220211121211020110112012 |
4 | 3010330201111322303000 |
5 | 3233220113320444210 |
6 | 44441233454352052 |
7 | 2564541112210646 |
oct | 304744125726300 |
9 | 52824554213465 |
10 | 13534001343680 |
11 | 4348812a22a24 |
12 | 1626b917bb628 |
13 | 77233517045c |
14 | 34b098c77196 |
15 | 1870b5332305 |
hex | c4f2157acc0 |
13534001343680 has 56 divisors (see below), whose sum is σ = 32228307605232. Its totient is φ = 5413522107392.
The previous prime is 13534001343673. The next prime is 13534001343701. The reversal of 13534001343680 is 8634310043531.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25103834 + ... + 25637286.
Almost surely, 213534001343680 is an apocalyptic number.
13534001343680 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13534001343680 is an abundant number, since it is smaller than the sum of its proper divisors (18694306261552).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13534001343680 is an equidigital number, since it uses as much as digits as its factorization.
13534001343680 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 612753 (or 612743 counting only the distinct ones).
The product of its (nonzero) digits is 311040, while the sum is 41.
The spelling of 13534001343680 in words is "thirteen trillion, five hundred thirty-four billion, one million, three hundred forty-three thousand, six hundred eighty".
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