Base | Representation |
---|---|
bin | 11110110010100001101010… |
… | …111000001011111001110000 |
3 | 122202110101222011202200012110 |
4 | 132302201222320023321300 |
5 | 120222103343114201000 |
6 | 1200000040242325320 |
7 | 40344206211516405 |
oct | 3662415270137160 |
9 | 582411864680173 |
10 | 135413522022000 |
11 | 3a168608a5a382 |
12 | 1323006a659840 |
13 | 5a73595552121 |
14 | 256209991c2ac |
15 | 109c63a87d850 |
hex | 7b286ae0be70 |
135413522022000 has 160 divisors (see below), whose sum is σ = 437024685487104. Its totient is φ = 36072928416000.
The previous prime is 135413522021977. The next prime is 135413522022001. The reversal of 135413522022000 is 220225314531.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (135413522022001) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5867556 + ... + 17471555.
Almost surely, 2135413522022000 is an apocalyptic number.
135413522022000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
135413522022000 is an abundant number, since it is smaller than the sum of its proper divisors (301611163465104).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
135413522022000 is a wasteful number, since it uses less digits than its factorization.
135413522022000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23340104 (or 23340088 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 30.
Adding to 135413522022000 its reverse (220225314531), we get a palindrome (135633747336531).
The spelling of 135413522022000 in words is "one hundred thirty-five trillion, four hundred thirteen billion, five hundred twenty-two million, twenty-two thousand".
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