13543141003411 has 2 divisors, whose sum is σ = 13543141003412. Its totient is φ = 13543141003410.

The previous prime is 13543141003339. The next prime is 13543141003451. The reversal of 13543141003411 is 11430014134531.

It is a strong prime.

It is an emirp because it is prime and its reverse (11430014134531) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13543141003411 is a prime.

It is a super-3 number, since 3×13543141003411³ (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (13543141003451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6771570501705 + 6771570501706.

It is an arithmetic number, because the mean of its divisors is an integer number (6771570501706).

Almost surely, 2^{13543141003411} is an apocalyptic number.

13543141003411 is a deficient number, since it is larger than the sum of its proper divisors (1).

13543141003411 is an equidigital number, since it uses as much as digits as its factorization.

13543141003411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 13543141003411 its reverse (11430014134531), we get a palindrome (24973155137942).

The spelling of 13543141003411 in words is "thirteen trillion, five hundred forty-three billion, one hundred forty-one million, three thousand, four hundred eleven".