Base | Representation |
---|---|
bin | 111111000110001110… |
… | …0110100111110000011 |
3 | 110221202020211011000211 |
4 | 1332030130310332003 |
5 | 4210001042302121 |
6 | 142125322454551 |
7 | 12534553000063 |
oct | 1761434647603 |
9 | 427666734024 |
10 | 135500353411 |
11 | 52513465055 |
12 | 22316964457 |
13 | ca155b0317 |
14 | 67b5bb53a3 |
15 | 37d0ba2ce1 |
hex | 1f8c734f83 |
135500353411 has 2 divisors, whose sum is σ = 135500353412. Its totient is φ = 135500353410.
The previous prime is 135500353403. The next prime is 135500353447. The reversal of 135500353411 is 114353005531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 135500353411 - 23 = 135500353403 is a prime.
It is not a weakly prime, because it can be changed into another prime (135500353211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67750176705 + 67750176706.
It is an arithmetic number, because the mean of its divisors is an integer number (67750176706).
Almost surely, 2135500353411 is an apocalyptic number.
135500353411 is a deficient number, since it is larger than the sum of its proper divisors (1).
135500353411 is an equidigital number, since it uses as much as digits as its factorization.
135500353411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13500, while the sum is 31.
Adding to 135500353411 its reverse (114353005531), we get a palindrome (249853358942).
The spelling of 135500353411 in words is "one hundred thirty-five billion, five hundred million, three hundred fifty-three thousand, four hundred eleven".
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