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135505502110146 = 2373226321478813
BaseRepresentation
bin11110110011110111010101…
…010100011000000111000010
3122202210012101102112021121210
4132303313111110120013002
5120230110232020011041
61200110211315030550
740353643443413610
oct3663672524300702
9582705342467553
10135505502110146
113a1a3619357a53
1213245a5a59b456
135a7c16366949c
1425667037b06b0
15109ec20988016
hex7b3dd55181c2

135505502110146 has 16 divisors (see below), whose sum is σ = 309726861966144. Its totient is φ = 38715857745744.

The previous prime is 135505502110007. The next prime is 135505502110159. The reversal of 135505502110146 is 641011205505531.

It is a super-2 number, since 2×1355055021101462 (a number of 29 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1613160739365 + ... + 1613160739448.

It is an arithmetic number, because the mean of its divisors is an integer number (19357928872884).

Almost surely, 2135505502110146 is an apocalyptic number.

135505502110146 is an abundant number, since it is smaller than the sum of its proper divisors (174221359855998).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

135505502110146 is a wasteful number, since it uses less digits than its factorization.

135505502110146 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3226321478825.

The product of its (nonzero) digits is 90000, while the sum is 39.

Adding to 135505502110146 its reverse (641011205505531), we get a palindrome (776516707615677).

The spelling of 135505502110146 in words is "one hundred thirty-five trillion, five hundred five billion, five hundred two million, one hundred ten thousand, one hundred forty-six".

Divisors: 1 2 3 6 7 14 21 42 3226321478813 6452642957626 9678964436439 19357928872878 22584250351691 45168500703382 67752751055073 135505502110146