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BaseRepresentation
bin111111100101101000…
…1101111101111111111
3111001110201012221000220
41333023101233233333
54214130412204210
6142422054552423
712602642234214
oct1771321575777
9431421187026
10136554413055
1152a04451725
122256b968713
13cb52a97658
146875b95b0b
1538434b1c70
hex1fcb46fbff

136554413055 has 16 divisors (see below), whose sum is σ = 218514265440. Its totient is φ = 72819952128.

The previous prime is 136554413053. The next prime is 136554413069. The reversal of 136554413055 is 550314455631.

It is a happy number.

It is not a de Polignac number, because 136554413055 - 21 = 136554413053 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 136554412998 and 136554413016.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (136554413053) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 441382 + ... + 684051.

It is an arithmetic number, because the mean of its divisors is an integer number (13657141590).

Almost surely, 2136554413055 is an apocalyptic number.

136554413055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

136554413055 is a deficient number, since it is larger than the sum of its proper divisors (81959852385).

136554413055 is a wasteful number, since it uses less digits than its factorization.

136554413055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1133530.

The product of its (nonzero) digits is 540000, while the sum is 42.

Adding to 136554413055 its reverse (550314455631), we get a palindrome (686868868686).

The spelling of 136554413055 in words is "one hundred thirty-six billion, five hundred fifty-four million, four hundred thirteen thousand, fifty-five".