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136824053053 = 178048473709
BaseRepresentation
bin111111101101101011…
…0010101110100111101
3111002011111121001120111
41333123112111310331
54220203424144203
6142504530150021
712612425155522
oct1773326256475
9432144531514
10136824053053
115303267a1a6
1222626122311
13cb968c564c
14689d905149
15385bec526d
hex1fdb595d3d

136824053053 has 4 divisors (see below), whose sum is σ = 144872526780. Its totient is φ = 128775579328.

The previous prime is 136824053039. The next prime is 136824053057. The reversal of 136824053053 is 350350428631.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 124882371769 + 11941681284 = 353387^2 + 109278^2 .

It is a cyclic number.

It is not a de Polignac number, because 136824053053 - 25 = 136824053021 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 136824052997 and 136824053015.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (136824053057) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4024236838 + ... + 4024236871.

It is an arithmetic number, because the mean of its divisors is an integer number (36218131695).

Almost surely, 2136824053053 is an apocalyptic number.

It is an amenable number.

136824053053 is a deficient number, since it is larger than the sum of its proper divisors (8048473727).

136824053053 is an equidigital number, since it uses as much as digits as its factorization.

136824053053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8048473726.

The product of its (nonzero) digits is 259200, while the sum is 40.

The spelling of 136824053053 in words is "one hundred thirty-six billion, eight hundred twenty-four million, fifty-three thousand, fifty-three".

Divisors: 1 17 8048473709 136824053053