Base | Representation |
---|---|
bin | 11111011000101101011111… |
… | …011101110000111111000000 |
3 | 200002202021001120211000222201 |
4 | 133120231133131300333000 |
5 | 121043101403211030410 |
6 | 1205325324432042544 |
7 | 41034612210564445 |
oct | 3730553735607700 |
9 | 602667046730881 |
10 | 138037555564480 |
11 | 3aa8a442536960 |
12 | 1359472a093454 |
13 | 5c03b68985540 |
14 | 26130a64dd9cc |
15 | 10e5a185e383a |
hex | 7d8b5f770fc0 |
138037555564480 has 224 divisors, whose sum is σ = 399483419106240. Its totient is φ = 44736550010880.
The previous prime is 138037555564459. The next prime is 138037555564541. The reversal of 138037555564480 is 84465555730831.
It is a super-2 number, since 2×1380375555644802 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (64).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 50682529 + ... + 53336608.
It is an arithmetic number, because the mean of its divisors is an integer number (1783408121010).
Almost surely, 2138037555564480 is an apocalyptic number.
138037555564480 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
138037555564480 is an abundant number, since it is smaller than the sum of its proper divisors (261445863541760).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
138037555564480 is a wasteful number, since it uses less digits than its factorization.
138037555564480 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 104019207 (or 104019197 counting only the distinct ones).
The product of its (nonzero) digits is 241920000, while the sum is 64.
The spelling of 138037555564480 in words is "one hundred thirty-eight trillion, thirty-seven billion, five hundred fifty-five million, five hundred sixty-four thousand, four hundred eighty".
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