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BaseRepresentation
bin10100010110110010011…
…001010011100001101101
311221201200202220010021221
4110112302121103201231
5140404324440133404
62550343131423341
7203030663165464
oct24266231234155
94851622803257
101398857349229
1149a28556190a
121a71365b4b51
13a1bb0c71c62
144b9c29679db
15265c2ba1954
hex145b265386d

1398857349229 has 2 divisors, whose sum is σ = 1398857349230. Its totient is φ = 1398857349228.

The previous prime is 1398857349167. The next prime is 1398857349299. The reversal of 1398857349229 is 9229437588931.

It is an a-pointer prime, because the next prime (1398857349299) can be obtained adding 1398857349229 to its sum of digits (70).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1010423019204 + 388434330025 = 1005198^2 + 623245^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1398857349229 is a prime.

It is a super-4 number, since 4×13988573492294 (a number of 50 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1398857349299) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 699428674614 + 699428674615.

It is an arithmetic number, because the mean of its divisors is an integer number (699428674615).

Almost surely, 21398857349229 is an apocalyptic number.

It is an amenable number.

1398857349229 is a deficient number, since it is larger than the sum of its proper divisors (1).

1398857349229 is an equidigital number, since it uses as much as digits as its factorization.

1398857349229 is an evil number, because the sum of its binary digits is even.

The product of its digits is 235146240, while the sum is 70.

The spelling of 1398857349229 in words is "one trillion, three hundred ninety-eight billion, eight hundred fifty-seven million, three hundred forty-nine thousand, two hundred twenty-nine".