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BaseRepresentation
bin10100010110110010011…
…001010011100010110100
311221201200202220010101120
4110112302121103202310
5140404324440134200
62550343131423540
7203030663165625
oct24266231234264
94851622803346
101398857349300
1149a285561974
121a71365b4bb0
13a1bb0c71cb8
144b9c2967a4c
15265c2ba19a0
hex145b26538b4

1398857349300 has 144 divisors (see below), whose sum is σ = 4108895555520. Its totient is φ = 367360266240.

The previous prime is 1398857349299. The next prime is 1398857349343. The reversal of 1398857349300 is 39437588931.

It is a Harshad number since it is a multiple of its sum of digits (60).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 98663812 + ... + 98677988.

Almost surely, 21398857349300 is an apocalyptic number.

1398857349300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1398857349300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2054447777760).

1398857349300 is an abundant number, since it is smaller than the sum of its proper divisors (2710038206220).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1398857349300 is a wasteful number, since it uses less digits than its factorization.

1398857349300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19170 (or 19163 counting only the distinct ones).

The product of its (nonzero) digits is 19595520, while the sum is 60.

The spelling of 1398857349300 in words is "one trillion, three hundred ninety-eight billion, eight hundred fifty-seven million, three hundred forty-nine thousand, three hundred".