14000000011 has 4 divisors (see below), whose sum is σ = 14006172400. Its totient is φ = 13993827624.

The previous prime is 13999999991. The next prime is 14000000057. The reversal of 14000000011 is 11000000041.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11000000041 = 31 ⋅354838711.

It is a cyclic number.

It is not a de Polignac number, because 14000000011 - 2⁷ = 13999999883 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13999999940 and 14000000003.

It is not an unprimeable number, because it can be changed into a prime (14000000081) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3082791 + ... + 3087328.

It is an arithmetic number, because the mean of its divisors is an integer number (3501543100).

Almost surely, 2^14000000011 is an apocalyptic number.

14000000011 is a deficient number, since it is larger than the sum of its proper divisors (6172389).

14000000011 is an equidigital number, since it uses as much as digits as its factorization.

14000000011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6172388.

The product of its (nonzero) digits is 4, while the sum is 7.

Adding to 14000000011 its reverse (11000000041), we get a palindrome (25000000052).

The spelling of 14000000011 in words is "fourteen billion, eleven", and thus it is an aban number.