Base | Representation |
---|---|
bin | 1000001001100101100… |
… | …0101000000100100111 |
3 | 111101101200212221212201 |
4 | 2002121120220010213 |
5 | 4243221123314421 |
6 | 144153141555331 |
7 | 13054431052513 |
oct | 2023130500447 |
9 | 441350787781 |
10 | 140012323111 |
11 | 54419340731 |
12 | 23175a15b47 |
13 | 102842b808b |
14 | 6ac3119143 |
15 | 3996d57b91 |
hex | 2099628127 |
140012323111 has 2 divisors, whose sum is σ = 140012323112. Its totient is φ = 140012323110.
The previous prime is 140012323079. The next prime is 140012323183. The reversal of 140012323111 is 111323210041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 140012323111 - 25 = 140012323079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140012323411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70006161555 + 70006161556.
It is an arithmetic number, because the mean of its divisors is an integer number (70006161556).
Almost surely, 2140012323111 is an apocalyptic number.
140012323111 is a deficient number, since it is larger than the sum of its proper divisors (1).
140012323111 is an equidigital number, since it uses as much as digits as its factorization.
140012323111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 140012323111 its reverse (111323210041), we get a palindrome (251335533152).
The spelling of 140012323111 in words is "one hundred forty billion, twelve million, three hundred twenty-three thousand, one hundred eleven".
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