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140113537 is a prime number
BaseRepresentation
bin10000101100111…
…11011010000001
3100202122111122021
420112133122001
5241332113122
621523041441
73320642164
oct1026373201
9322574567
10140113537
11720aa413
123ab10281
1323049c25
1414873adb
15c47a1c7
hex859f681

140113537 has 2 divisors, whose sum is σ = 140113538. Its totient is φ = 140113536.

The previous prime is 140113517. The next prime is 140113579. The reversal of 140113537 is 735311041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 95277121 + 44836416 = 9761^2 + 6696^2 .

It is a cyclic number.

It is not a de Polignac number, because 140113537 - 27 = 140113409 is a prime.

It is not a weakly prime, because it can be changed into another prime (140113517) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70056768 + 70056769.

It is an arithmetic number, because the mean of its divisors is an integer number (70056769).

Almost surely, 2140113537 is an apocalyptic number.

It is an amenable number.

140113537 is a deficient number, since it is larger than the sum of its proper divisors (1).

140113537 is an equidigital number, since it uses as much as digits as its factorization.

140113537 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1260, while the sum is 25.

The square root of 140113537 is about 11836.9564077933. The cubic root of 140113537 is about 519.3897389724.

Adding to 140113537 its reverse (735311041), we get a palindrome (875424578).

The spelling of 140113537 in words is "one hundred forty million, one hundred thirteen thousand, five hundred thirty-seven".