140121532252341 has 12 divisors (see below), whose sum is σ = 202397871626860. Its totient is φ = 93414307380480.

The previous prime is 140121532252301. The next prime is 140121532252363. The reversal of 140121532252341 is 143252235121041.

140121532252341 is a `hidden beast` number, since 1 + 4 + 0 + 1 + 21 + 53 + 22 + 523 + 41 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 8488453115025 + 131633079137316 = 2913495^2 + 11473146^2 .

It is not a de Polignac number, because 140121532252341 - 2¹⁰ = 140121532251317 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140121532252296 and 140121532252305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140121532252301) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 31112901 + ... + 35330661.

Almost surely, 2^{140121532252341} is an apocalyptic number.

It is an amenable number.

140121532252341 is a deficient number, since it is larger than the sum of its proper divisors (62276339374519).

140121532252341 is a wasteful number, since it uses less digits than its factorization.

140121532252341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7909076 (or 7909073 counting only the distinct ones).

The product of its (nonzero) digits is 57600, while the sum is 36.

Adding to 140121532252341 its reverse (143252235121041), we get a palindrome (283373767373382).

The spelling of 140121532252341 in words is "one hundred forty trillion, one hundred twenty-one billion, five hundred thirty-two million, two hundred fifty-two thousand, three hundred forty-one".