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BaseRepresentation
bin11111110111000010010110…
…001001111100000100010001
3200101010111011111121122021202
4133313002112021330010101
5121331222344224034213
61214002535425000545
741341306123265534
oct3767022611740421
9611114144548252
10140121532252433
1140713231aa5296
12138705a9783155
1360255331a02c4
142685cbdd30a1b
15112ed38c5cb58
hex7f709627c111

140121532252433 has 2 divisors, whose sum is σ = 140121532252434. Its totient is φ = 140121532252432.

The previous prime is 140121532252381. The next prime is 140121532252459. The reversal of 140121532252433 is 334252235121041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 138642311974609 + 1479220277824 = 11774647^2 + 1216232^2 .

It is a cyclic number.

It is not a de Polignac number, because 140121532252433 - 218 = 140121531990289 is a prime.

It is not a weakly prime, because it can be changed into another prime (140121532257433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70060766126216 + 70060766126217.

It is an arithmetic number, because the mean of its divisors is an integer number (70060766126217).

Almost surely, 2140121532252433 is an apocalyptic number.

It is an amenable number.

140121532252433 is a deficient number, since it is larger than the sum of its proper divisors (1).

140121532252433 is an equidigital number, since it uses as much as digits as its factorization.

140121532252433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 172800, while the sum is 38.

Adding to 140121532252433 its reverse (334252235121041), we get a palindrome (474373767373474).

The spelling of 140121532252433 in words is "one hundred forty trillion, one hundred twenty-one billion, five hundred thirty-two million, two hundred fifty-two thousand, four hundred thirty-three".