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140121532252451 = 711973542707781
BaseRepresentation
bin11111110111000010010110…
…001001111100000100100011
3200101010111011111121122022102
4133313002112021330010203
5121331222344224034301
61214002535425001015
741341306123265561
oct3767022611740443
9611114144548272
10140121532252451
1140713231aa5302
12138705a978316b
1360255331a0309
142685cbdd30a31
15112ed38c5cb6b
hex7f709627c123

140121532252451 has 4 divisors (see below), whose sum is σ = 142095074960304. Its totient is φ = 138147989544600.

The previous prime is 140121532252433. The next prime is 140121532252459. The reversal of 140121532252451 is 154252235121041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-140121532252451 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140121532252459) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 986771353820 + ... + 986771353961.

It is an arithmetic number, because the mean of its divisors is an integer number (35523768740076).

Almost surely, 2140121532252451 is an apocalyptic number.

140121532252451 is a deficient number, since it is larger than the sum of its proper divisors (1973542707853).

140121532252451 is an equidigital number, since it uses as much as digits as its factorization.

140121532252451 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1973542707852.

The product of its (nonzero) digits is 96000, while the sum is 38.

Adding to 140121532252451 its reverse (154252235121041), we get a palindrome (294373767373492).

The spelling of 140121532252451 in words is "one hundred forty trillion, one hundred twenty-one billion, five hundred thirty-two million, two hundred fifty-two thousand, four hundred fifty-one".

Divisors: 1 71 1973542707781 140121532252451