Base | Representation |
---|---|
bin | 11111110111000010111001… |
… | …011000111110001100001011 |
3 | 200101010112200200221211121102 |
4 | 133313002321120332030023 |
5 | 121331230102042131401 |
6 | 1214003114223132015 |
7 | 41341326562026662 |
oct | 3767027130761413 |
9 | 611115620854542 |
10 | 140122123395851 |
11 | 40713505754073 |
12 | 1387073374400b |
13 | 60255c87b78cc |
14 | 2685d3864ddd9 |
15 | 112ed70acb56b |
hex | 7f70b963e30b |
140122123395851 has 2 divisors, whose sum is σ = 140122123395852. Its totient is φ = 140122123395850.
The previous prime is 140122123395799. The next prime is 140122123395901. The reversal of 140122123395851 is 158593321221041.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-140122123395851 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 140122123395796 and 140122123395805.
It is not a weakly prime, because it can be changed into another prime (140122123295851) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70061061697925 + 70061061697926.
It is an arithmetic number, because the mean of its divisors is an integer number (70061061697926).
Almost surely, 2140122123395851 is an apocalyptic number.
140122123395851 is a deficient number, since it is larger than the sum of its proper divisors (1).
140122123395851 is an equidigital number, since it uses as much as digits as its factorization.
140122123395851 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 518400, while the sum is 47.
The spelling of 140122123395851 in words is "one hundred forty trillion, one hundred twenty-two billion, one hundred twenty-three million, three hundred ninety-five thousand, eight hundred fifty-one".
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