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BaseRepresentation
bin11111110111000010111001…
…011000111110001100111101
3200101010112200200221211200021
4133313002321120332030331
5121331230102042132101
61214003114223132141
741341326562030063
oct3767027130761475
9611115620854607
10140122123395901
1140713505754109
1213870733744051
1360255c87b793a
142685d38650033
15112ed70acb5a1
hex7f70b963e33d

140122123395901 has 2 divisors, whose sum is σ = 140122123395902. Its totient is φ = 140122123395900.

The previous prime is 140122123395851. The next prime is 140122123395913. The reversal of 140122123395901 is 109593321221041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 94919696670276 + 45202426725625 = 9742674^2 + 6723275^2 .

It is a cyclic number.

It is not a de Polignac number, because 140122123395901 - 211 = 140122123393853 is a prime.

It is a super-2 number, since 2×1401221233959012 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140122123396901) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70061061697950 + 70061061697951.

It is an arithmetic number, because the mean of its divisors is an integer number (70061061697951).

Almost surely, 2140122123395901 is an apocalyptic number.

It is an amenable number.

140122123395901 is a deficient number, since it is larger than the sum of its proper divisors (1).

140122123395901 is an equidigital number, since it uses as much as digits as its factorization.

140122123395901 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 116640, while the sum is 43.

The spelling of 140122123395901 in words is "one hundred forty trillion, one hundred twenty-two billion, one hundred twenty-three million, three hundred ninety-five thousand, nine hundred one".