Base | Representation |
---|---|
bin | 1100101111100111111011… |
… | …0010001010110000000001 |
3 | 1211121120020000010001212022 |
4 | 3023321332302022300001 |
5 | 3314034202430300001 |
6 | 45445055545411225 |
7 | 2644233054130424 |
oct | 313717662126001 |
9 | 54546200101768 |
10 | 14012310400001 |
11 | 4512650a14391 |
12 | 16a381a499b15 |
13 | 7a84804b81c4 |
14 | 3662b13a99bb |
15 | 19475ba3411b |
hex | cbe7ec8ac01 |
14012310400001 has 4 divisors (see below), whose sum is σ = 14012700392532. Its totient is φ = 14011920407472.
The previous prime is 14012310399953. The next prime is 14012310400027. The reversal of 14012310400001 is 10000401321041.
It is a happy number.
14012310400001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 8831000890000 + 5181309510001 = 2971700^2 + 2276249^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14012310400001 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (14012310400061) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 194942366 + ... + 195014231.
It is an arithmetic number, because the mean of its divisors is an integer number (3503175098133).
Almost surely, 214012310400001 is an apocalyptic number.
It is an amenable number.
14012310400001 is a deficient number, since it is larger than the sum of its proper divisors (389992531).
14012310400001 is an equidigital number, since it uses as much as digits as its factorization.
14012310400001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 389992530.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 14012310400001 its reverse (10000401321041), we get a palindrome (24012711721042).
It can be divided in two parts, 14012 and 310400001, that added together give a palindrome (310414013).
The spelling of 14012310400001 in words is "fourteen trillion, twelve billion, three hundred ten million, four hundred thousand, one".
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