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14014050113 = 717472505641
BaseRepresentation
bin11010000110100110…
…10110111101000001
31100011122220111201002
431003103112331001
5212200044100423
610234333421345
71004165313650
oct150323267501
940148814632
1014014050113
115a416252a8
12287133a855
1314244bb05b
1496d2d3197
155704ab228
hex3434d6f41

14014050113 has 16 divisors (see below), whose sum is σ = 17318997504. Its totient is φ = 11064906240.

The previous prime is 14014050073. The next prime is 14014050131. The reversal of 14014050113 is 31105041041.

It is a happy number.

14014050113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a cyclic number.

It is not a de Polignac number, because 14014050113 - 28 = 14014049857 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14014050143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1247228 + ... + 1258413.

It is an arithmetic number, because the mean of its divisors is an integer number (1082437344).

Almost surely, 214014050113 is an apocalyptic number.

It is an amenable number.

14014050113 is a deficient number, since it is larger than the sum of its proper divisors (3304947391).

14014050113 is a wasteful number, since it uses less digits than its factorization.

14014050113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2505712.

The product of its (nonzero) digits is 240, while the sum is 20.

Adding to 14014050113 its reverse (31105041041), we get a palindrome (45119091154).

The spelling of 14014050113 in words is "fourteen billion, fourteen million, fifty thousand, one hundred thirteen".

Divisors: 1 7 17 47 119 329 799 5593 2505641 17539487 42595897 117765127 298171279 824355889 2002007159 14014050113