Base | Representation |
---|---|
bin | 10100011011100110111… |
… | …001010110000111111000 |
3 | 11222020001111001002010002 |
4 | 110123212321112013320 |
5 | 141000424440143000 |
6 | 2553000502412132 |
7 | 203303151462323 |
oct | 24334671260770 |
9 | 4866044032102 |
10 | 1404033131000 |
11 | 4a14a1110305 |
12 | 1a813ba31048 |
13 | a2527358716 |
14 | 4bd541057ba |
15 | 267c727b8d5 |
hex | 146e6e561f8 |
1404033131000 has 64 divisors (see below), whose sum is σ = 3286014994080. Its totient is φ = 561514540800.
The previous prime is 1404033130987. The next prime is 1404033131063. The reversal of 1404033131000 is 1313304041.
It is a super-2 number, since 2×14040331310002 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5706524 + ... + 5947476.
Almost surely, 21404033131000 is an apocalyptic number.
1404033131000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1404033131000 is an abundant number, since it is smaller than the sum of its proper divisors (1881981863080).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1404033131000 is a wasteful number, since it uses less digits than its factorization.
1404033131000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 246801 (or 246787 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 1404033131000 its reverse (1313304041), we get a palindrome (1405346435041).
The spelling of 1404033131000 in words is "one trillion, four hundred four billion, thirty-three million, one hundred thirty-one thousand".
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