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140527375253641 = 562324991530367
BaseRepresentation
bin11111111100111100010100…
…010010001000000010001001
3200102120021201101211020002201
4133330330110102020002021
5121404400031031104031
61214513215053000201
741412524235005515
oct3774742422100211
9612507641736081
10140527375253641
114085a363875a02
1213917191783061
1360548a01c79bc
14269b7c0115145
15113a68d5cad61
hex7fcf14488089

140527375253641 has 4 divisors (see below), whose sum is σ = 140552366789632. Its totient is φ = 140502383717652.

The previous prime is 140527375253611. The next prime is 140527375253677. The reversal of 140527375253641 is 146352573725041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140527375253641 - 25 = 140527375253609 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140527375253611) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12495759561 + ... + 12495770806.

It is an arithmetic number, because the mean of its divisors is an integer number (35138091697408).

Almost surely, 2140527375253641 is an apocalyptic number.

It is an amenable number.

140527375253641 is a deficient number, since it is larger than the sum of its proper divisors (24991535991).

140527375253641 is an equidigital number, since it uses as much as digits as its factorization.

140527375253641 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24991535990.

The product of its (nonzero) digits is 21168000, while the sum is 55.

The spelling of 140527375253641 in words is "one hundred forty trillion, five hundred twenty-seven billion, three hundred seventy-five million, two hundred fifty-three thousand, six hundred forty-one".

Divisors: 1 5623 24991530367 140527375253641