Base | Representation |
---|---|
bin | 1100110101010111101110… |
… | …1001011010011101100111 |
3 | 1211222000001210002002112020 |
4 | 3031111323221122131213 |
5 | 3322143403224134343 |
6 | 50002305002554223 |
7 | 2654326530065550 |
oct | 315257351323547 |
9 | 54860053062466 |
10 | 14111042021223 |
11 | 455050638a764 |
12 | 16ba993508973 |
13 | 7b48862b1854 |
14 | 36ad99bbb327 |
15 | 1970d9727b83 |
hex | cd57ba5a767 |
14111042021223 has 8 divisors (see below), whose sum is σ = 21502540222848. Its totient is φ = 8063452583544.
The previous prime is 14111042021221. The next prime is 14111042021233. The reversal of 14111042021223 is 32212024011141.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 14111042021223 - 21 = 14111042021221 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14111042021193 and 14111042021202.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14111042021221) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 335977190961 + ... + 335977191002.
It is an arithmetic number, because the mean of its divisors is an integer number (2687817527856).
Almost surely, 214111042021223 is an apocalyptic number.
14111042021223 is a deficient number, since it is larger than the sum of its proper divisors (7391498201625).
14111042021223 is an equidigital number, since it uses as much as digits as its factorization.
14111042021223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 671954381973.
The product of its (nonzero) digits is 768, while the sum is 24.
Adding to 14111042021223 its reverse (32212024011141), we get a palindrome (46323066032364).
The spelling of 14111042021223 in words is "fourteen trillion, one hundred eleven billion, forty-two million, twenty-one thousand, two hundred twenty-three".
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