Base | Representation |
---|---|
bin | 1100110101011011011011… |
… | …0011000110001101011011 |
3 | 1211222002121221102221111000 |
4 | 3031112312303012031123 |
5 | 3322202421302243301 |
6 | 50002551253240043 |
7 | 2654363240231310 |
oct | 315266663061533 |
9 | 54862557387430 |
10 | 14112034415451 |
11 | 4550975589185 |
12 | 16bb00b933023 |
13 | 7b49b3a87b7b |
14 | 36b051908d07 |
15 | 197146905786 |
hex | cd5b6cc635b |
14112034415451 has 16 divisors (see below), whose sum is σ = 23893391603200. Its totient is φ = 8064019665864.
The previous prime is 14112034415447. The next prime is 14112034415503. The reversal of 14112034415451 is 15451443021141.
14112034415451 is a `hidden beast` number, since 1 + 4 + 1 + 1 + 203 + 441 + 5 + 4 + 5 + 1 = 666.
It is not a de Polignac number, because 14112034415451 - 22 = 14112034415447 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14112034415431) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 37333424191 + ... + 37333424568.
It is an arithmetic number, because the mean of its divisors is an integer number (1493336975200).
Almost surely, 214112034415451 is an apocalyptic number.
14112034415451 is a deficient number, since it is larger than the sum of its proper divisors (9781357187749).
14112034415451 is an equidigital number, since it uses as much as digits as its factorization.
14112034415451 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 74666848775 (or 74666848769 counting only the distinct ones).
The product of its (nonzero) digits is 38400, while the sum is 36.
Adding to 14112034415451 its reverse (15451443021141), we get a palindrome (29563477436592).
The spelling of 14112034415451 in words is "fourteen trillion, one hundred twelve billion, thirty-four million, four hundred fifteen thousand, four hundred fifty-one".
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