14112034415541 has 6 divisors (see below), whose sum is σ = 20384049711350. Its totient is φ = 9408022943688.

The previous prime is 14112034415503. The next prime is 14112034415657. The reversal of 14112034415541 is 14551443021141.

14112034415541 is a `hidden beast` number, since 1 + 4 + 1 + 1 + 203 + 441 + 5 + 5 + 4 + 1 = 666.

It can be written as a sum of positive squares in only one way, i.e., 14048598437316 + 63435978225 = 3748146^2 + 251865^2 .

It is not a de Polignac number, because 14112034415541 - 2²¹ = 14112032318389 is a prime.

It is a super-2 number, since 2×14112034415541² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14112034415496 and 14112034415505.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14112034415441) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 784001911966 + ... + 784001911983.

Almost surely, 2^{14112034415541} is an apocalyptic number.

It is an amenable number.

14112034415541 is a deficient number, since it is larger than the sum of its proper divisors (6272015295809).

14112034415541 is a wasteful number, since it uses less digits than its factorization.

14112034415541 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1568003823955 (or 1568003823952 counting only the distinct ones).

The product of its (nonzero) digits is 38400, while the sum is 36.

Adding to 14112034415541 its reverse (14551443021141), we get a palindrome (28663477436682).

The spelling of 14112034415541 in words is "fourteen trillion, one hundred twelve billion, thirty-four million, four hundred fifteen thousand, five hundred forty-one".