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14112034415543 = 131910699040497
BaseRepresentation
bin1100110101011011011011…
…0011000110001110110111
31211222002121221102221121102
43031112312303012032313
53322202421302244133
650002551253240315
72654363240231501
oct315266663061667
954862557387542
1014112034415543
114550975589259
1216bb00b93309b
137b49b3a87c1c
1436b051908d71
151971469057e8
hexcd5b6cc63b7

14112034415543 has 4 divisors (see below), whose sum is σ = 14122733457360. Its totient is φ = 14101335373728.

The previous prime is 14112034415503. The next prime is 14112034415657. The reversal of 14112034415543 is 34551443021141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14112034415543 - 210 = 14112034414519 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14112034415497 and 14112034415506.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14112034415503) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5349518930 + ... + 5349521567.

It is an arithmetic number, because the mean of its divisors is an integer number (3530683364340).

Almost surely, 214112034415543 is an apocalyptic number.

14112034415543 is a deficient number, since it is larger than the sum of its proper divisors (10699041817).

14112034415543 is a wasteful number, since it uses less digits than its factorization.

14112034415543 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10699041816.

The product of its (nonzero) digits is 115200, while the sum is 38.

Adding to 14112034415543 its reverse (34551443021141), we get a palindrome (48663477436684).

The spelling of 14112034415543 in words is "fourteen trillion, one hundred twelve billion, thirty-four million, four hundred fifteen thousand, five hundred forty-three".

Divisors: 1 1319 10699040497 14112034415543