Base | Representation |
---|---|
bin | 1100110101011011011011… |
… | …0011000111010011101011 |
3 | 1211222002121221110011122112 |
4 | 3031112312303013103223 |
5 | 3322202421302414242 |
6 | 50002551253312535 |
7 | 2654363240250362 |
oct | 315266663072353 |
9 | 54862557404575 |
10 | 14112034419947 |
11 | 45509755915a2 |
12 | 16bb00b93574b |
13 | 7b49b3a89c29 |
14 | 36b05190a7d9 |
15 | 197146906c82 |
hex | cd5b6cc74eb |
14112034419947 has 2 divisors, whose sum is σ = 14112034419948. Its totient is φ = 14112034419946.
The previous prime is 14112034419941. The next prime is 14112034420009. The reversal of 14112034419947 is 74991443021141.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14112034419947 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14112034419895 and 14112034419904.
It is not a weakly prime, because it can be changed into another prime (14112034419941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7056017209973 + 7056017209974.
It is an arithmetic number, because the mean of its divisors is an integer number (7056017209974).
Almost surely, 214112034419947 is an apocalyptic number.
14112034419947 is a deficient number, since it is larger than the sum of its proper divisors (1).
14112034419947 is an equidigital number, since it uses as much as digits as its factorization.
14112034419947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 870912, while the sum is 50.
The spelling of 14112034419947 in words is "fourteen trillion, one hundred twelve billion, thirty-four million, four hundred nineteen thousand, nine hundred forty-seven".
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