Base | Representation |
---|---|
bin | 100000000101100110011111… |
… | …001111101101100111001001 |
3 | 200111200011121112201000222021 |
4 | 200011212133033231213021 |
5 | 121444122200002003001 |
6 | 1220050424030324441 |
7 | 41503520634051424 |
oct | 4005463717554711 |
9 | 614604545630867 |
10 | 141122412141001 |
11 | 40a69751666515 |
12 | 139b2576359721 |
13 | 6098a2b840465 |
14 | 26bc50b17a9bb |
15 | 114adb787bba1 |
hex | 80599f3ed9c9 |
141122412141001 has 2 divisors, whose sum is σ = 141122412141002. Its totient is φ = 141122412141000.
The previous prime is 141122412140989. The next prime is 141122412141047. The reversal of 141122412141001 is 100141214221141.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 125727422054976 + 15394990086025 = 11212824^2 + 3923645^2 .
It is a cyclic number.
It is not a de Polignac number, because 141122412141001 - 219 = 141122411616713 is a prime.
It is not a weakly prime, because it can be changed into another prime (141122412141901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70561206070500 + 70561206070501.
It is an arithmetic number, because the mean of its divisors is an integer number (70561206070501).
Almost surely, 2141122412141001 is an apocalyptic number.
It is an amenable number.
141122412141001 is a deficient number, since it is larger than the sum of its proper divisors (1).
141122412141001 is an equidigital number, since it uses as much as digits as its factorization.
141122412141001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 512, while the sum is 25.
Adding to 141122412141001 its reverse (100141214221141), we get a palindrome (241263626362142).
The spelling of 141122412141001 in words is "one hundred forty-one trillion, one hundred twenty-two billion, four hundred twelve million, one hundred forty-one thousand, one".
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