Base | Representation |
---|---|
bin | 1100110101111100010010… |
… | …0000100100000110001011 |
3 | 1211222221101121202012100001 |
4 | 3031133010200210012023 |
5 | 3322324002204411442 |
6 | 50011010403423431 |
7 | 2655124635515443 |
oct | 315370440440613 |
9 | 54887347665301 |
10 | 14120854372747 |
11 | 4554691188691 |
12 | 1700871684b77 |
13 | 7b578b14aa05 |
14 | 36b64b055123 |
15 | 1974b0dbb2b7 |
hex | cd7c482418b |
14120854372747 has 4 divisors (see below), whose sum is σ = 14121380884576. Its totient is φ = 14120327860920.
The previous prime is 14120854372733. The next prime is 14120854372753. The reversal of 14120854372747 is 74727345802141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14120854372747 - 243 = 5324761350539 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14120854379747) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 263215683 + ... + 263269324.
It is an arithmetic number, because the mean of its divisors is an integer number (3530345221144).
Almost surely, 214120854372747 is an apocalyptic number.
14120854372747 is a deficient number, since it is larger than the sum of its proper divisors (526511829).
14120854372747 is an equidigital number, since it uses as much as digits as its factorization.
14120854372747 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 526511828.
The product of its (nonzero) digits is 10536960, while the sum is 55.
The spelling of 14120854372747 in words is "fourteen trillion, one hundred twenty billion, eight hundred fifty-four million, three hundred seventy-two thousand, seven hundred forty-seven".
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