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141354534423103 is a prime number
BaseRepresentation
bin100000001000111110101010…
…110011111100101000111111
3200112111100202112201201120121
4200020332222303330220333
5122011423041303014403
61220345213204355411
741526346064643601
oct4010765263745077
9615440675651517
10141354534423103
11410491376386a1
1213a2b5576a5b67
1360b48a1b14641
1426c984b4b3171
151151e50de43bd
hex808faacfca3f

141354534423103 has 2 divisors, whose sum is σ = 141354534423104. Its totient is φ = 141354534423102.

The previous prime is 141354534423071. The next prime is 141354534423187. The reversal of 141354534423103 is 301324435453141.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 141354534423103 - 25 = 141354534423071 is a prime.

It is a super-2 number, since 2×1413545344231032 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 141354534423103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141354534423803) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70677267211551 + 70677267211552.

It is an arithmetic number, because the mean of its divisors is an integer number (70677267211552).

Almost surely, 2141354534423103 is an apocalyptic number.

141354534423103 is a deficient number, since it is larger than the sum of its proper divisors (1).

141354534423103 is an equidigital number, since it uses as much as digits as its factorization.

141354534423103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1036800, while the sum is 43.

Adding to 141354534423103 its reverse (301324435453141), we get a palindrome (442678969876244).

The spelling of 141354534423103 in words is "one hundred forty-one trillion, three hundred fifty-four billion, five hundred thirty-four million, four hundred twenty-three thousand, one hundred three".