141433132331 has 2 divisors, whose sum is σ = 141433132332. Its totient is φ = 141433132330.

The previous prime is 141433132303. The next prime is 141433132381. The reversal of 141433132331 is 133231334141.

It is a weak prime.

It is an emirp because it is prime and its reverse (133231334141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 141433132331 - 2¹⁴ = 141433115947 is a prime.

It is a super-2 number, since 2×141433132331² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 141433132294 and 141433132303.

It is not a weakly prime, because it can be changed into another prime (141433132381) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70716566165 + 70716566166.

It is an arithmetic number, because the mean of its divisors is an integer number (70716566166).

Almost surely, 2^141433132331 is an apocalyptic number.

141433132331 is a deficient number, since it is larger than the sum of its proper divisors (1).

141433132331 is an equidigital number, since it uses as much as digits as its factorization.

141433132331 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7776, while the sum is 29.

Adding to 141433132331 its reverse (133231334141), we get a palindrome (274664466472).

The spelling of 141433132331 in words is "one hundred forty-one billion, four hundred thirty-three million, one hundred thirty-two thousand, three hundred thirty-one".