Search a number
-
+
142011115511 is a prime number
BaseRepresentation
bin1000010001000010000…
…1011010011111110111
3111120112222222010120212
42010100201122133313
54311314321144021
6145123343020035
713155111364556
oct2042041323767
9446488863525
10142011115511
1155254632a81
122363329a61b
131051242b885
146c3277bd9d
153a6257c85b
hex211085a7f7

142011115511 has 2 divisors, whose sum is σ = 142011115512. Its totient is φ = 142011115510.

The previous prime is 142011115501. The next prime is 142011115513. The reversal of 142011115511 is 115511110241.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 142011115511 - 222 = 142006921207 is a prime.

It is a super-2 number, since 2×1420111155112 (a number of 23 digits) contains 22 as substring.

Together with 142011115513, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142011115513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71005557755 + 71005557756.

It is an arithmetic number, because the mean of its divisors is an integer number (71005557756).

Almost surely, 2142011115511 is an apocalyptic number.

142011115511 is a deficient number, since it is larger than the sum of its proper divisors (1).

142011115511 is an equidigital number, since it uses as much as digits as its factorization.

142011115511 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 200, while the sum is 23.

Adding to 142011115511 its reverse (115511110241), we get a palindrome (257522225752).

The spelling of 142011115511 in words is "one hundred forty-two billion, eleven million, one hundred fifteen thousand, five hundred eleven".