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142011115555 = 528402223111
BaseRepresentation
bin1000010001000010000…
…1011010100000100011
3111120112222222010122111
42010100201122200203
54311314321144210
6145123343020151
713155111364651
oct2042041324043
9446488863574
10142011115555
1155254633011
122363329a657
131051242b8ba
146c3277bdd1
153a6257c88a
hex211085a823

142011115555 has 4 divisors (see below), whose sum is σ = 170413338672. Its totient is φ = 113608892440.

The previous prime is 142011115513. The next prime is 142011115573. The reversal of 142011115555 is 555511110241.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 555511110241 = 2324152656967.

It is not a de Polignac number, because 142011115555 - 229 = 141474244643 is a prime.

It is a Smith number, since the sum of its digits (31) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14201111551 + ... + 14201111560.

It is an arithmetic number, because the mean of its divisors is an integer number (42603334668).

Almost surely, 2142011115555 is an apocalyptic number.

142011115555 is a deficient number, since it is larger than the sum of its proper divisors (28402223117).

142011115555 is an equidigital number, since it uses as much as digits as its factorization.

142011115555 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28402223116.

The product of its (nonzero) digits is 5000, while the sum is 31.

Adding to 142011115555 its reverse (555511110241), we get a palindrome (697522225796).

The spelling of 142011115555 in words is "one hundred forty-two billion, eleven million, one hundred fifteen thousand, five hundred fifty-five".

Divisors: 1 5 28402223111 142011115555