Base | Representation |
---|---|
bin | 10100101011100001011… |
… | …000101011101000101111 |
3 | 12000212011100000222100221 |
4 | 110223201120223220233 |
5 | 141240423330121341 |
6 | 3004504225232211 |
7 | 204446456243605 |
oct | 24534130535057 |
9 | 5025140028327 |
10 | 1421120551471 |
11 | 4a876a559205 |
12 | 1ab50a492667 |
13 | a401b4a98ca |
14 | 4cad565d875 |
15 | 26e77470ed1 |
hex | 14ae162ba2f |
1421120551471 has 2 divisors, whose sum is σ = 1421120551472. Its totient is φ = 1421120551470.
The previous prime is 1421120551457. The next prime is 1421120551511. The reversal of 1421120551471 is 1741550211241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1421120551471 - 25 = 1421120551439 is a prime.
It is a super-3 number, since 3×14211205514713 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1421120551451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710560275735 + 710560275736.
It is an arithmetic number, because the mean of its divisors is an integer number (710560275736).
Almost surely, 21421120551471 is an apocalyptic number.
1421120551471 is a deficient number, since it is larger than the sum of its proper divisors (1).
1421120551471 is an equidigital number, since it uses as much as digits as its factorization.
1421120551471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11200, while the sum is 34.
The spelling of 1421120551471 in words is "one trillion, four hundred twenty-one billion, one hundred twenty million, five hundred fifty-one thousand, four hundred seventy-one".
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