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14212000000 = 2856111719
BaseRepresentation
bin11010011110001100…
…11110100100000000
31100200110101101220101
431033012132210000
5213101233000000
610310124252144
71012121002222
oct151706364400
940613341811
1014212000000
116033337a50
1229076a1054
131456508173
1498b700412
15582a5ce6a
hex34f19e900

14212000000 has 504 divisors, whose sum is σ = 43115073120. Its totient is φ = 4608000000.

The previous prime is 14211999937. The next prime is 14212000009. The reversal of 14212000000 is 21241.

It is a Harshad number since it is a multiple of its sum of digits (10).

It is not an unprimeable number, because it can be changed into a prime (14212000009) by changing a digit.

It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 747999991 + ... + 748000009.

It is an arithmetic number, because the mean of its divisors is an integer number (85545780).

Almost surely, 214212000000 is an apocalyptic number.

14212000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 14212000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21557536560).

14212000000 is an abundant number, since it is smaller than the sum of its proper divisors (28903073120).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14212000000 is an frugal number, since it uses more digits than its factorization.

14212000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 93 (or 54 counting only the distinct ones).

The product of its (nonzero) digits is 16, while the sum is 10.

Adding to 14212000000 its reverse (21241), we get a palindrome (14212021241).

The spelling of 14212000000 in words is "fourteen billion, two hundred twelve million", and thus it is an aban number.